(SPOJ) Tiro ao Alvo - Solution
Link to the problem: http://br.spoj.com/problems/ALVO13/
For every coordinate of a shot, the solution below calculates the distance between the shot and the center of the target. Then, using this information, we can call a Binary Search to find out how many circles cover this shot.
import java.io.*;
import java.util.*;
class Main {
public long[] radius;
public int binSearch(int lo, int hi, long value) {
if (lo > hi) {
return lo;
}
int m = (lo+hi)/2;
if (radius[m] > value) {
return binSearch(lo, m-1, value);
}
if (radius[m] < value) {
return binSearch(m+1, hi, value);
}
else {
return m;
}
}
public static long reader(BufferedReader br) throws NumberFormatException, IOException {
long n;
long resp = 0;
int sinal = 1;
while (true) {
n = br.read();
if (n >= '0' && n <= '9') {
break;
}
if (n == '-') {
sinal = -1;
}
if (n == '+') {
sinal = 1;
}
}
while (true) {
resp = resp*10 + n-'0';
n = br.read();
if (n < '0' || n > '9') {
break;
}
}
return resp*sinal;
}
public void process() throws NumberFormatException, IOException {
BufferedReader br = new BufferedReader(new InputStreamReader(System.in));
BufferedWriter bw = new BufferedWriter(new OutputStreamWriter(System.out));
String line = br.readLine();
String[] s = line.split(" ");
int numCircles = Integer.parseInt(s[0]);
int numShots = Integer.parseInt(s[1]);
radius = new long[numCircles];
for (int i = 0; i < numCircles; i++) {
long n = reader(br);
radius[i] = n*n; // avoid to do sqrt to calculate de distance
}
long points = 0;
for (int i = 0; i < numShots; i++) {
long x = reader(br);
long y = reader(br);
long dist = x*x+y*y;
int radiusIndex = binSearch(0, numCircles-1, dist);
points += (numCircles-radiusIndex);
}
bw.write(points+"\n");
bw.flush();
bw.close();
return;
}
public static void main(String[] args) throws NumberFormatException, IOException {
Main m = new Main();
m.process();
System.exit(0);
}
}
For every coordinate of a shot, the solution below calculates the distance between the shot and the center of the target. Then, using this information, we can call a Binary Search to find out how many circles cover this shot.
import java.io.*;
import java.util.*;
class Main {
public long[] radius;
public int binSearch(int lo, int hi, long value) {
if (lo > hi) {
return lo;
}
int m = (lo+hi)/2;
if (radius[m] > value) {
return binSearch(lo, m-1, value);
}
if (radius[m] < value) {
return binSearch(m+1, hi, value);
}
else {
return m;
}
}
public static long reader(BufferedReader br) throws NumberFormatException, IOException {
long n;
long resp = 0;
int sinal = 1;
while (true) {
n = br.read();
if (n >= '0' && n <= '9') {
break;
}
if (n == '-') {
sinal = -1;
}
if (n == '+') {
sinal = 1;
}
}
while (true) {
resp = resp*10 + n-'0';
n = br.read();
if (n < '0' || n > '9') {
break;
}
}
return resp*sinal;
}
public void process() throws NumberFormatException, IOException {
BufferedReader br = new BufferedReader(new InputStreamReader(System.in));
BufferedWriter bw = new BufferedWriter(new OutputStreamWriter(System.out));
String line = br.readLine();
String[] s = line.split(" ");
int numCircles = Integer.parseInt(s[0]);
int numShots = Integer.parseInt(s[1]);
radius = new long[numCircles];
for (int i = 0; i < numCircles; i++) {
long n = reader(br);
radius[i] = n*n; // avoid to do sqrt to calculate de distance
}
long points = 0;
for (int i = 0; i < numShots; i++) {
long x = reader(br);
long y = reader(br);
long dist = x*x+y*y;
int radiusIndex = binSearch(0, numCircles-1, dist);
points += (numCircles-radiusIndex);
}
bw.write(points+"\n");
bw.flush();
bw.close();
return;
}
public static void main(String[] args) throws NumberFormatException, IOException {
Main m = new Main();
m.process();
System.exit(0);
}
}
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