(UVA) Hamiltonian Cycle - Solution
Link to the solution: https://uva.onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=24&page=show_problem&problem=716
The solution below used Backtracking to try to find a Hamiltonian Cycle.
import java.io.*;
import java.util.*;
class Main {
public ArrayList<ArrayList<Integer>> adjList;
public HashSet<Integer> visited;
public ArrayList<Integer> orderVisit;
public ArrayList<Integer> answer;
public int numVertices;
public boolean found;
public int start;
public void rec(int curr) {
if (visited.size() == numVertices && adjList.get(curr).contains(start)) {
answer = (ArrayList<Integer>) orderVisit.clone();
answer.add(start);
found = true;
return;
}
ArrayList<Integer> reachVertices = adjList.get(curr);
for (int i = 0; i < reachVertices.size(); i++) {
if (found) {
return;
}
if (visited.contains(reachVertices.get(i))) {
continue;
}
visited.add(reachVertices.get(i));
orderVisit.add(reachVertices.get(i));
rec(reachVertices.get(i));
orderVisit.remove(orderVisit.size()-1);
visited.remove(reachVertices.get(i));
}
}
public void process() throws NumberFormatException, IOException {
Scanner sc = new Scanner(System.in);
BufferedWriter bw = new BufferedWriter(new OutputStreamWriter(System.out));
while (sc.hasNext()) {
numVertices = sc.nextInt();
adjList = new ArrayList<>();
for (int i = 0; i <= numVertices; i++) {
adjList.add(new ArrayList<Integer>());
}
String n = sc.next();
while (!n.equals("%")) {
int n1 = Integer.parseInt(n);
int n2 = sc.nextInt();
adjList.get(n1).add(n2);
adjList.get(n2).add(n1);
n = sc.next();
}
found = false;
answer = new ArrayList<>();
orderVisit = new ArrayList<>();
visited = new HashSet<>();
visited.add(1);
orderVisit.add(1);
start = 1;
rec(1);
if (answer.size() > 0) {
for (int i = 0; i < answer.size(); i++) {
if (i == answer.size()-1) {
bw.write(answer.get(i)+"\n");
break;
}
bw.write(answer.get(i)+" ");
}
} else {
bw.write("N\n");
}
}
bw.flush();
bw.close();
return;
}
public static void main(String[] args) throws NumberFormatException, IOException {
Main m = new Main();
m.process();
System.exit(0);
}
}
The solution below used Backtracking to try to find a Hamiltonian Cycle.
import java.io.*;
import java.util.*;
class Main {
public ArrayList<ArrayList<Integer>> adjList;
public HashSet<Integer> visited;
public ArrayList<Integer> orderVisit;
public ArrayList<Integer> answer;
public int numVertices;
public boolean found;
public int start;
public void rec(int curr) {
if (visited.size() == numVertices && adjList.get(curr).contains(start)) {
answer = (ArrayList<Integer>) orderVisit.clone();
answer.add(start);
found = true;
return;
}
ArrayList<Integer> reachVertices = adjList.get(curr);
for (int i = 0; i < reachVertices.size(); i++) {
if (found) {
return;
}
if (visited.contains(reachVertices.get(i))) {
continue;
}
visited.add(reachVertices.get(i));
orderVisit.add(reachVertices.get(i));
rec(reachVertices.get(i));
orderVisit.remove(orderVisit.size()-1);
visited.remove(reachVertices.get(i));
}
}
public void process() throws NumberFormatException, IOException {
Scanner sc = new Scanner(System.in);
BufferedWriter bw = new BufferedWriter(new OutputStreamWriter(System.out));
while (sc.hasNext()) {
numVertices = sc.nextInt();
adjList = new ArrayList<>();
for (int i = 0; i <= numVertices; i++) {
adjList.add(new ArrayList<Integer>());
}
String n = sc.next();
while (!n.equals("%")) {
int n1 = Integer.parseInt(n);
int n2 = sc.nextInt();
adjList.get(n1).add(n2);
adjList.get(n2).add(n1);
n = sc.next();
}
found = false;
answer = new ArrayList<>();
orderVisit = new ArrayList<>();
visited = new HashSet<>();
visited.add(1);
orderVisit.add(1);
start = 1;
rec(1);
if (answer.size() > 0) {
for (int i = 0; i < answer.size(); i++) {
if (i == answer.size()-1) {
bw.write(answer.get(i)+"\n");
break;
}
bw.write(answer.get(i)+" ");
}
} else {
bw.write("N\n");
}
}
bw.flush();
bw.close();
return;
}
public static void main(String[] args) throws NumberFormatException, IOException {
Main m = new Main();
m.process();
System.exit(0);
}
}
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