(UVA) Scrolling Sign - Solution
Link to the problem: https://uva.onlinejudge.org/index.php?option=onlinejudge&page=show_problem&problem=2623
Some comments can be found in the code below.
import java.io.*;
import java.util.*;
class Main {
public void process() throws NumberFormatException, IOException {
Scanner sc = new Scanner(System.in);
BufferedWriter bw = new BufferedWriter(new OutputStreamWriter(System.out));
int numTests = sc.nextInt();
for (int test = 0; test < numTests; test++) {
int numCharactersOnSign = sc.nextInt();
int numWords = sc.nextInt();
String[] words = new String[numWords];
for (int i = 0; i < numWords; i++) {
words[i] = sc.next();
}
StringBuilder sb = new StringBuilder();
for (int i = 0; i < words.length; i++) {
int start = 0;
for (int j = sb.length()-1; j >= Math.max(0, sb.length()-numCharactersOnSign); j--) {
// if it does not match, and there is no chance that the new word matches somehow with the previous word
if (words[i].charAt(0) != sb.charAt(j) && sb.length()-j >= words[i].length()) {
break;
}
// if the first character of the new word matches with a character of the previous word, I check the next characters
if (words[i].charAt(0) == sb.charAt(j)) {
boolean possible = true;
int l = 1;
for (int k = j+1; k < sb.length() && l < words[i].length(); k++, l++) {
if (words[i].charAt(l) != sb.charAt(k)) { // if the sequence does not match
possible = false;
}
}
if (possible) { // if the sequence matches, I do not need some first characters of the new word
start = l;
}
}
}
sb.append(words[i].substring(start, words[i].length()));
}
bw.write(sb.length()+"\n");
}
bw.flush();
bw.close();
return;
}
public static void main(String[] args) throws NumberFormatException, IOException {
Main m = new Main();
m.process();
System.exit(0);
}
}
Some comments can be found in the code below.
import java.io.*;
import java.util.*;
class Main {
public void process() throws NumberFormatException, IOException {
Scanner sc = new Scanner(System.in);
BufferedWriter bw = new BufferedWriter(new OutputStreamWriter(System.out));
int numTests = sc.nextInt();
for (int test = 0; test < numTests; test++) {
int numCharactersOnSign = sc.nextInt();
int numWords = sc.nextInt();
String[] words = new String[numWords];
for (int i = 0; i < numWords; i++) {
words[i] = sc.next();
}
StringBuilder sb = new StringBuilder();
for (int i = 0; i < words.length; i++) {
int start = 0;
for (int j = sb.length()-1; j >= Math.max(0, sb.length()-numCharactersOnSign); j--) {
// if it does not match, and there is no chance that the new word matches somehow with the previous word
if (words[i].charAt(0) != sb.charAt(j) && sb.length()-j >= words[i].length()) {
break;
}
// if the first character of the new word matches with a character of the previous word, I check the next characters
if (words[i].charAt(0) == sb.charAt(j)) {
boolean possible = true;
int l = 1;
for (int k = j+1; k < sb.length() && l < words[i].length(); k++, l++) {
if (words[i].charAt(l) != sb.charAt(k)) { // if the sequence does not match
possible = false;
}
}
if (possible) { // if the sequence matches, I do not need some first characters of the new word
start = l;
}
}
}
sb.append(words[i].substring(start, words[i].length()));
}
bw.write(sb.length()+"\n");
}
bw.flush();
bw.close();
return;
}
public static void main(String[] args) throws NumberFormatException, IOException {
Main m = new Main();
m.process();
System.exit(0);
}
}
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